You can use factoring to show that the sum of two multiples of 3 is also a multiple of 3. If m and n are integers, then 3m and 3n are multiples of three. 3m + 3n = 3(m + n). Since m + n is an integer, 3(m + n) is a multiple of three. a. Show that if an integer is one more than a multiple of 3, then its square is also one more than a multiple of 3. b. If an integer is two more than a multiple of 3, is its square also two more than a multiple of 3? Explain.
