A sealed mailing tube in the shape of a cylinder has a radius of 2 inches and is 10 inches long.
What is the surface area of the sealed mailing tube?
Use 3.14 to pi
Enter your answer in the box.
in2

Respuesta :

Answer:

150.72 in²

Step-by-step explanation:

To find the surface area of the cylindrical sealed mailing tube, we can use the formula for the surface area of a cylinder:

[tex]\boxed{\begin{array}{l}\underline{\textsf{Surface Area of a Cylinder}}\\\\SA=2\pi rh+2\pi r^2\\\\\textsf{where:}\\\phantom{ww}\bullet\;\textsf{$SA$ is the surface area.}\\\phantom{ww}\bullet\;\textsf{$r$ is the radius of the circular base.}\\\phantom{ww}\bullet\;\textsf{$h$ is the height.}\end{array}}[/tex]

Given values:

  • r = 2 in
  • h = 10 in
  • π = 3.14

Substitute the given values into the formula and solve for SA:

[tex]SA=2\cdot 3.14 \cdot 2 \cdot 10+2 \cdot 3.14 \cdot 2^2\\\\SA=2\cdot 3.14 \cdot 2 \cdot 10+2 \cdot 3.14 \cdot 4\\\\SA=6.28 \cdot 2 \cdot 10+6.28 \cdot 4\\\\SA=12.56 \cdot 10+25.12\\\\SA=125.6+25.12\\\\SA=150.72\; \sf in^2[/tex]

Therefore, the surface area of the sealed mailing tube is:

[tex]\LARGE\boxed{\boxed{150.72\; \sf in^2}}[/tex]

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