Question

how many Liters of a 12.0 M concentrate would you need to make 5.0 L of a 2.0 M solution

Answer 1

Answer:

$V_1 = 0.833L$

Explanation:

To determine how many liters of a 12.0 M concentrate are needed to make 5.0 L of a 2.0 M solution, we will use the dilution formula:

$M_{1} V_{1} = M_{2} V_{2}$

$M_1$ is the initial concentration.

$M_2$ is the final concentration.

$V_1$ is the initial volume.

$V_2$ is the final volume.

In this problem, we are given the initial concentration of 12.0 M and is asked what's the initial volume we would need to make the final concentration of 2.0 M and final volume of 5.0 L .

So let's put in the given values into the equation.

$(12.0 M)(V_1)=(2.0 M)(5.0L)$

Multiply:

$(12.0 M)(V_1)=(10.0 MV)$

Divide 12.0 M to both sides to find $V_1$.

$V_1 = \frac{10}{12} L$ or $V_1 = 0.833L$

So, you would need 0.833 liters of the 12.0 M concentrate.