Question

Two cars emerge side by side from a tunnel. car a is traveling with a speed of 60km/h and has an acceleration of 40km/h/min. car b has a speed of 40km/h and has an acceleration of 60 km/h/min. which car is passing the other as they come out of the tunnel?

Answer 1

To solve this problem, we have to make use of the formula:

d = v0 t + 0.5 a t^2

 

What we can do is to assume a time, t = 1 h.

 

For Car A:

d = 60 * 1 + 0.5 (40 * 60) * 1^2

d = 1,260 km

 

For Car B:

d = 40 * 1 + 0.5 (60 * 60) * 1^2

d = 1,840 km

 

Since Car B travelled the larger distance, so it is the Car which passes the other as they come out.

 

Answer:

Car B

Answer 2

Car A will pass Car B first when they come out of the tunnel.

       To solve this question, we just need to use simple logic.

• Car A and Car B come out side by side from a tunnel. This means they were at at same position when coming from the tunnel.

• Now, we are told that Car A was moving with a speed of 60km/h while Car B was moving with a speed of 40 km/h.

• This means that car A will pass Car B first because it was coming out with a higher initial speed.

Read more at; brainly.in/question/32785997