Answer:
[tex]41.21.28\text{cm}^2[/tex]
Step-by-step explanation:
[tex]\text{Solution:}\\\text{Here, the remaining length of leg of each triangle = }\sqrt{40.5^2-24.3^2}=32.4\text{cm}[/tex]
[tex]\text{So the area of two right triangles = }2\times\dfrac{1}{2}\times24.3\times32.4=787.32\text{cm}^2[/tex]
[tex]\text{Area of the three rectangles = }34.3\times24.3+40.5\times34.3+32.4\times34.3\\\text{}\qquad\qquad\qquad\qquad\qquad\qquad\quad\text{=}3333.96\text{cm}^2[/tex]
[tex]\text{Therefore, surface area of the figure = Area of (two triangles + three rectangles)}\\\text{}\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\text{=}787.32+3333.96\\\text{}\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\text{=}4121.28\text{cm}^2[/tex]
