Consider the reaction BaF₂ -> Ba²+ Write the equilibrium constant expression and find its value for the following reaction.
a) [Ba²+] / [F⁻]², K = 1.7 x 10⁻6
b) [BaF₂] / [Ba²+], K = 2.0 x 10⁻6
c) [Ba²+] / [BaF₂], K = 1.7 x 10⁶
d) [BaF₂] / [F⁻]², K = 2.0 x 10⁶
