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msm555

Answer:

[tex]\sf SA = 125 \, \textsf{in}^2 [/tex]

Step-by-step explanation:

The total surface area ([tex]A[/tex]) of a square-based pyramid can be calculated using the formula:

[tex] \Large\boxed{\boxed{\sf SA = B + \dfrac{1}{2}Pl}} [/tex]

where

  • [tex] \sf B[/tex] is the area of the base,
  • [tex]\sf P[/tex] is the perimeter of the base, and
  • [tex]\sf l[/tex] is the slant height.

For a square base, the area of the base ([tex]B[/tex]) is the side length squared ([tex]s^2[/tex]).

Given that the base side length ([tex]s[/tex]) is 5 in and the slant height ([tex]l[/tex]) is 10 in:

Calculate the area of the base ([tex]B[/tex]):

[tex]\sf B = s^2 \\\\ = 5^2 \\\\= 25 \, \textsf{in}^2 [/tex]

Calculate the perimeter of the base ([tex]P[/tex]) for a square:

[tex] \sf P = 4s\\\\ = 4 \times 5 \\\\= 20 \, \textsf{in} [/tex]

Substitute the values into the formula for the total surface area ([tex]A[/tex]):

[tex]\sf SA = B + \dfrac{1}{2}Pl [/tex]

[tex] \sf SA = 25 + \dfrac{1}{2} \times 20 \times 10 [/tex]

[tex] \sf SA = 25 + 100 [/tex]

[tex]\sf SA = 125 \, \textsf{in}^2 [/tex]

So, the total surface area of the square-based pyramid is:. [tex]125 \, \textsf{in}^2[/tex]

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