A theater has 60 seats in the first row, 68 seats in the second row and 76 seats in the third row , and so on in the same increasing pattern. (a) if the theater has 20 rows of seats, how many seats are in a theater? (b) find the sum of the first 12 positive even integers.

Respuesta :

Answer:

There are a total of 2720 seats in the theater.

The sum of the first 12 positive even integers is 156.

Step-by-step explanation:

(a) To find the total number of seats in the theater with 20 rows, we can use the arithmetic series formula:

Sₙ = n/2 ×(a₁+aₙ)

where:

Sₙ  is the sum of the series,

n is the number of terms in the series (number of rows),

a₁ is the first term of the series (number of seats in the first row),

aₙ is the last term of the series (number of seats in the last row).

Given:

n=20 (number of rows),

a₁ =60 (number of seats in the first row),

The pattern is increasing by 8 seats each row.

We need to find a, the number of seats in the 20th row.

a₂₀=a₁ +(n−1)×d

a₂₀=60+(20−1)×8

a₂₀=60+19×8

a₂₀ =60+152

a₂₀ =212

Now, we can calculate the sum of the series:

S₂₀= 20/2 ×(60+212)

S₂₀=10×272

S₂₀ =2720

So, there are a total of 2720 seats in the theater.

(b) The sum of the first 12 positive even integers can be found using the formula for the sum of an arithmetic series:

Sₙ = n/2 ×(a₁ + aₙ)

where:

Sₙ is the sum of the series,

n is the number of terms in the series,

a₁ is the first term of the series,

aₙ is the last term of the series.

Given:

n=12 (number of terms),

a₁ =2 (first even integer),

a₁₂ =2×12=24 (last even integer).

Using the formula:

S₁₂ =12/2 ×(2+24)

S₁₂ =6×26

S₁₂ =156

So, the sum of the first 12 positive even integers is 156.

ACCESS MORE