Question

Can someone please answer problem #2? The answer is right next to it. Please show your work. This is algebra 2 by the way.​

Answer 1

Answer:

$(f + g)(x) = -4\sqrt[3]{5x}$

Step-by-step explanation:

2)

To find $(f + g)(x)$, we add $f(x)$ and $g(x)$.

Given:

• $f(x) = -\sqrt[3]{5x}$
• $g(x) = -3\sqrt[3]{5x}$

We perform $(f + g)(x)$ as follows:

$(f + g)(x) = f(x) + g(x)$

$(f + g)(x) = (-\sqrt[3]{5x}) + (-3\sqrt[3]{5x})$

$(f + g)(x) = -\sqrt[3]{5x} - 3\sqrt[3]{5x}$

To combine these terms, notice that they share the same radical term. So we can add them directly:

$(f + g)(x) = (-1 - 3)\sqrt[3]{5x}$

$(f + g)(x) = -4\sqrt[3]{5x}$

So, $(f + g)(x) = -4\sqrt[3]{5x}$.