QUESTION 3:
To determine the peak voltage across the resistor (VR1) in the circuit shown, we can use the second approximation model for the diode, which is commonly known as the "ideal diode" model.
In this model, the diode behaves as a perfect switch that conducts current in the forward direction (when the diode is on) and blocks current in the reverse direction (when the diode is off).
Given:
- Peak voltage of the input signal (V1) = 120 Vpk
- Frequency (f) = 60 Hz
- Phase angle (θ) = 0°
- Second approximation peak voltage of the diode (Vpk) = 10.2 Vp
The peak voltage across the resistor (VR1) in a half-wave rectifier circuit using an ideal diode is approximately equal to the peak voltage of the input signal minus the peak voltage of the diode.
\[ VR1 = V1 - Vpk \]
Substitute the values:
\[ VR1 = 120 \, \text{V} - 10.2 \, \text{V} \]
\[ VR1 = 109.8 \, \text{V} \]
Therefore, the peak voltage across the resistor (VR1) in the circuit is approximately 109.8 V.
QUESTION 4:
The waveform shown represents the output voltage waveform from a half-wave rectifier.
Therefore, the correct answer is:
- Half wave rectifier
