Respuesta :
Answer :
- 1,953
Explanation :
The exponential function is given by,
- y = a(b)^x
here,
- a = initial value
- b = growth rate
- y = no. of books sold
- x = time period
atq,
- a = 640
- b = (books sold during 2nd month)/(books sold during 1st month) = 800/640 = 1.25
- y = ?
- x = 5
plugging in the values,
- y = 640(1.25)^5
- y = 640*3.05175..
- y ≈ 1,953
therefore, Dean would have sold nearly an amount of 1,953 books by December.
Answer:
1953 books
Step-by-step explanation:
To model the monthly number of books sold, [tex] y [/tex], [tex] x [/tex] months after publishing, we can use an exponential equation in the form:
[tex] \Large \boxed{\boxed{y = a \cdot b^x}} [/tex],
where:
- [tex] a [/tex] represents the initial number of books sold.
- [tex] b [/tex] represents the growth rate or multiplicative factor.
Given the information:
- In July (the first month), Dean sold 640 books.
- In August (the second month), Dean sold 800 books.
We can use these data points to find the values of [tex] a [/tex] and [tex] b [/tex].
- Use July's data: [tex] a = 640 [/tex].
- Use August's data: [tex] 800 = a \cdot b^1 [/tex] (since August is the second month).
Now, we can solve for [tex] b [/tex]:
[tex] b = \dfrac{800}{a} \\\\= \dfrac{800}{640} \\\\= \dfrac{5}{4} = 1.25 [/tex]
Therefore, our exponential equation becomes:
[tex] y = 640 \times (1.25)^x [/tex]
To find the number of books Dean can expect to sell in December (5 months after publishing), substitute [tex] x = 5 [/tex] into the equation:
[tex] y = 640 \times (1.25)^5 [/tex]
[tex] y \approx 640 \times 3.051757813 [/tex]
[tex] y \approx 1953.125 [/tex]
[tex] y \approx 1953\textsf{ (in nearest whole number)}[/tex]
To the nearest whole number, Dean can expect to sell approximately 1953 books during the month of December, 5 months after publishing.