Question

Find the vertex of the parabola y = x2 – 10x + 16.

Answer 1

Answer:

vertex = (5, - 9 )

Step-by-step explanation:

given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

The x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

y = x² - 10x + 16 ← is in standard form

with a = 1, b = - 10 , then

$x_{vertex}$ = - $\frac{-10}{2(1)}$ = - $\frac{-10}{2}$ = - (- 5) = 5

substitute x = 5 into the function y, for corresponding value of y

y = 5² - 10(5) + 16 = 25 - 50 + 16 = - 9

vertex = (5, - 9 )