Question

solve 8x+3y=11;3x-y=2 by elimination method

Answer 1

Answer:

X=1 & Y=1

Step-by-step explanation:

8x+3y=11 then 3(3x-y)=2*3

Then add both equations

8x+3y=11

+

9x-3y=6

--------------

17x+0=17

Solve for by dividing by 17 both sides to get x=1,

Subsitute for x on either one of the initial equations

3(1)-y=2

3-2=y

Therefore y=1

Answer 2

Answer:

$x=1 \text{ and }y=1$

Step-by-step explanation:

$8x+3y=11......(1)\\3x-y=2......(2)\\\\\text{Multiplying equation(2) by 3,}\\3(3x-y)=3(2)\\\text{or, }9x-3y=6.......(3)$

$\text{Adding equation(1) and (3),}\\\text{}\quad\text{}8x+3y=11\\+9x-3y=6\\\text{or, }17x=17\\\text{or, }x=1$

$\text{Equation(2) becomes:}\\3(1)-y=2\\\text{or, }3-y=2\\\therefore\ y=1$

$\therefore\ x=1,y=1$