Answer:
(2,11)
Step-by-step explanation:
Let's assume the problem is finding a solution to the linear equations, which means we want to know where (or if) these two lines intersect. They are both linear equations, so let's rearrange them to the standard slope-intercept format of y=mx + b, where m is the slope and b is the y-intercept (the value of y when x is zero).
2x+y=15
y = -2x + 15
y = 4x+3 is already in standard format.
The slopes of the two lines are different -2 and 4), so they are not parallel. They will intersect somewhere (only once).
For them to intersect, both will have a solution, (x,y) at which the lines intersect. Since we know that the value of y will be equal at some point, set the other side of the two equations equal to each other:
-2x + 15 = 4x+3
Now solve for x:
-6x = -12
x = 2
If x = 2, find y for one of the equations:
y = -2x + 15 for x = 2
y = -2*2 + 15
y = 11
The point (2, 11) is a solution for y = -2 + 15
Find y for the second equation for x = 2:
y = 4x+3 for x = 2
y = 4*2 + 3
y = 11
The solution is (2,11)
Both lines intersect at (2,11)
See the attached graph.
