Answer:
(5, -8)
Step-by-step explanation:
We can find the solution to the system of equations:
[tex]\begin{cases}-5x+y\!\!\!\!&=-33\\ \ \ \ x+4y\!\!\!\!&=-27\end{cases}[/tex]
using the elimination method.
First, we can multiply both sides of the first equation by 4:
[tex]4(-5x + y = -33)[/tex]
↓↓↓
[tex]-20x + 4y = -132[/tex]
Next, we can subtract the second equation from the multiplied first equation:
[tex](-20x + 4y = -132)[/tex]
[tex]\underline{-\ \ \, (x + 4y = -27)}[/tex]
[tex]-21x + 0y = -132 - (-27)[/tex]
Using the resulting equation, we can solve for the x-coordinate of the solution:
[tex]-21x = -132 + 27[/tex]
[tex]-21x = -105[/tex]
[tex]\boxed{x = 5}[/tex]
We can now substitute this x-coordinate into one of the original equations to solve for the y-coordinate. I will use the second equation:
[tex]x + 4y = -27[/tex]
[tex]5 + 4y = -27[/tex]
[tex]4y = -32[/tex]
[tex]\boxed{y=-8}[/tex]
Finally, we can put these coordinates together into a solution set:
[tex]\boxed{(5, -8)}[/tex]
Further Note
If we graph both of the equations on a Cartesian plane, the solution set is the point where the lines intersect.