A restaurant that serves a buffet lunch has one price for adults and another price for children under 12. The Jung group has two adults and three children and their bill is $48.95. The Harvey group has three adults and two children. Their bill is $52.05. What is the price of the buffet for an adult? for a child?

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Answer:

So, the price of the buffet for an adult is $11.65 and for a child is $8.55.

Step-by-step explanation:

Let's denote the price for an adult's buffet lunch as \( A \) and the price for a child's buffet lunch as \( C \).

We have two equations based on the given information:

1. For the Jung group:

  \[ 2A + 3C = 48.95 \]

2. For the Harvey group:

  \[ 3A + 2C = 52.05 \]

We can solve this system of linear equations to find the values of \( A \) and \( C \).

Multiplying the first equation by 3 and the second equation by 2, we get:

1. \( 6A + 9C = 146.85 \)

2. \( 6A + 4C = 104.10 \)

Now, subtract the second equation from the first to eliminate \( A \):

\[ (6A + 9C) - (6A + 4C) = 146.85 - 104.10 \]

\[ 5C = 42.75 \]

\[ C = \frac{42.75}{5} = 8.55 \]

Now, substitute the value of \( C \) into one of the original equations to find \( A \). Let's use the first equation:

\[ 2A + 3(8.55) = 48.95 \]

\[ 2A + 25.65 = 48.95 \]

\[ 2A = 48.95 - 25.65 \]

\[ 2A = 23.3 \]

\[ A = \frac{23.3}{2} = 11.65 \]

So, the price of the buffet for an adult is $11.65 and for a child is $8.55.

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