Answer:
a) 4.28 rad
b) μ = ω²r / g
Explanation:
(a) Given:
ω₀ = 0 rad/s
ω = 33⅓ rpm × (2π rad/rev) × (1 min / 60 s) = 3.49 rad/s
t = 2.45 s
Find: Δθ
Δθ = ½ (ω + ω₀) t
Δθ = ½ (3.49 rad/s + 0 rad/s) (2.45 s)
Δθ = 4.28 rad
(b) Draw a free body diagram of the dime. There are 3 forces:
Weight force mg pulling down,
Normal force N pushing up,
Friction force Nμ pushing towards the center.
Sum of forces in the y direction:
∑F = ma
N − mg = 0
N = mg
Sum of forces in the centripetal direction:
∑F = ma
Nμ = m v²/r
mgμ = m ω²r
μ = ω²r / g