Answer:
C. [tex]\sf \overline{AB} \cong \overline{DE} [/tex]
Step-by-step explanation:
The SAS Axiom, also known as the Side-Angle-Side axiom, is a fundamental principle in Euclidean geometry. It states that , if two triangles have two sides that are equal in length and the included angle between these sides is equal, then the two triangles are congruent.
In this case:
[tex]\sf \overline{AC} \cong \overline{DP} [/tex] Given
[tex]\sf \angle A \cong \angle D [/tex] Given
The remaining additional information, is the side.
So
Here
The side between [tex]\sf \angle A [/tex] and [tex] \angle D [/tex] is [tex] \sf \overline{AB } [/tex] and [tex] \sf \overline{DE} [/tex] respectively.
So, the remaining additional information to prove [tex]\sf \triangle ABC \cong \triangle DEF [/tex] by side-angle-side is:
C. [tex]\sf \overline{AB} \cong \overline{DE} [/tex]