Question

Help!!! due in 30 mins

Answer 1

The diagram shows a right triangle with sides a, b, and c, where a=20, b=20, and c is the hypotenuse. You want to find the approximate value of side BD.

We can use the Pythagorean theorem to solve for c, In this case, we have

c² = a² + b²

Substituting of a and b, we get

c² =20² +20²

c² =800

Taking the square root of both sides, we get

c = $\sqrt{800}$

c ≈ 28.28

you need to round c to two decimal places. Therefore, the approximate value of side BD is

28.28

Answer 2

Answer:

$5.36$

Step-by-step explanation:

$\text{Solution: }\\\text{Here, Angles A and B are equal because AB = BC.}\\\therefore\angle\text{A}=\angle\text{B}=15^\circ+30^\circ+15^\circ=60^\circ\\\text{Now, }\\\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ\ \ \ [\text{Sum of angles of triangle is }180^\circ.]\\\text{or, }60^\circ+60^\circ+\angle\text{C}=180^\circ\\\text{or, }\angle\text{C}=60^\circ$

$\text{Hence, triangle ABC is an equilateral triangle. }$

$\text{Also, triangles ACE and ABD will be congruent triangles by A.S.A. postulate.}$

$\therefore\ \text{BD = CE as they are corresponding sides of congruent triangles.}$

$\text{BC = BD + DE + CE}\\\text{or, }20\approx\text{BD + 9.28 + BD}\\\text{or, 10.72}\approx2\text{BD}\\\text{or, BD}\approx5.36$