Question

Find the single equation of the pair of straight lines parallel to the lines pair represented by the equation x^2+2xy+y^2-2x-2y-15=0 and passing through the origin.

Answer 1

Answer:

y = -x

Step-by-step explanation:

Find the slope of the line that is parallel to x^2+2xy+y^2-2x-2y-15=0:

m = -1

Substitute: m= -1, x=0, y=0 into y=mx+b:

0=-0+b

b=0

Substitute : m=-1, b=0 into y=mx+b:

y=-x