A farmer wants to divide 8085 ha of grazing into 9 or 15 camps of equal size.How did he know,without doing a long division calculation,that the 15 camp division is an easier practical solution than the 9 camp division?

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Answer:

To determine if the 15 camp division is an easier practical solution than the 9 camp division without doing a long division calculation, the farmer can use the concept of divisibility.

For the 9 camp division, the farmer would need to divide 8085 ha into 9 equal-sized camps. To determine if this is a practical solution, the farmer can check if 8085 is divisible by 9.

One way to check for divisibility by 9 is to add up the digits of the number and see if the sum is divisible by 9. In this case, 8 + 0 + 8 + 5 = 21. Since 21 is not divisible by 9, we can conclude that 8085 is not divisible by 9.

On the other hand, for the 15 camp division, the farmer would need to divide 8085 ha into 15 equal-sized camps. To determine if this is a practical solution, the farmer can check if 8085 is divisible by 15.

Similarly, to check for divisibility by 15, the farmer can check if the sum of the digits is divisible by 3 and if the last digit is either 0 or 5. In this case, 8 + 0 + 8 + 5 = 21, which is divisible by 3, and the last digit is 5. Therefore, we can conclude that 8085 is divisible by 15.

Based on this analysis, the farmer can determine that the 15 camp division is an easier practical solution than the 9 camp division, as 8085 is divisible by 15 but not by 9.

#Hope it helps :)

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