How many ways are there to select 9 countries in the United Nations to serve on a council if 1 is selected from a block of 53, 1 are selected from a block of 66 and 7 are selected from the remaining 70 countries?

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Answer:

Step-by-step explanation:

The number of ways to select countries from each block can be calculated using the combination formula:

$ C(n, k) = \frac{n!}{k!(n-k)!} $

where:

- n is the total number of items,

- k is the number of items to choose,

- "!" denotes factorial.

So, the number of ways to select 1 country from a block of 53 is:

$ C(53, 1) = \frac{53!}{1!(53-1)!} = 53 $

The number of ways to select 1 country from a block of 66 is:

$ C(66, 1) = \frac{66!}{1!(66-1)!} = 66 $

The number of ways to select 7 countries from the remaining 70 is:

$ C(70, 7) = \frac{70!}{7!(70-7)!} $

The total number of ways to select 9 countries is the product of the number of ways to select from each block:

$ 53 \times 66 \times C(70, 7) $

This gives the total number of ways to select 9 countries from the United Nations to serve on a council under the given conditions.

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