Question

A vector ⃗ has a magnitude of 5 units and it has a direction along a vector = 3i+ 2j- 2k
Write down the vector ⃗ in unit vector notation

Answer 1

Answer: Given that the magnitude of vector v is 5 units, we have:

|

|

=

5

Therefore, the unit vector u in the direction of vector v is:

=

5

Substitute the values of vector v into the equation:

=

3

�

+

2

�

−

2

�

5

Simplify to get the unit vector in unit vector notation:

=

3

5

�

+

2

5

�

−

2

5

�

Therefore, the vector ⃗ in unit vector notation is:

3

5

�

+

2

5

�

−

2

5

�

Explanation: