Respuesta :
[tex]\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ -5}}\quad ,&{{ 1}})\quad
% (c,d)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies\cfrac{3}{2}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=\cfrac{3}{2}(x-(-5))\\
\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-1=\cfrac{3}{2}(x+5)[/tex]
Answer: The correct option is D, i.e., y − 1 = three halves(x + 5).
Explanation:
It is given that the line passing through the point (−5, 1) with a slope of three halves.
The equation of line passing through the point [tex](x_1,y_1)[/tex] with slope m is defined as,
[tex]y-y_1=m(x-x_1)[/tex]
It is a point slope form.
Since we have point (-5,1) and slope three halves. Put these value in the above point slope form.
[tex]y-1=\text{three halves}(x-(-5))[/tex]
[tex]y-1=\text{three halves}(x+5)[/tex]
This equation is same as equation is shown in option D, therefore the option D is correct.