Question

What is the value of x to the nearest tenth? 
 

       A. 9.7   B. 8.1   C. 5.9   D. 7.9

Answer 1

Use the Pythagorean theorem. The equation for this right triangle would be a^2+b^2=c^2. Since you have one leg and the hypotenuse, you can plug these into the equation. It would be 7^2+b^2=12^2. Do the exponents. You will get 49+b^2=144. You need to get b by itself so subtract each side by 49. You get the equation b^2=95. Square root each side to get b=9.746. This rounds to 9.7. So the answer is A. Hope this helps! ;)

Answer 2

Answer:

A) x = 9.7

Step-by-step explanation:

Given  : A triangle

To find : What is the value of x to the nearest tenth.

Solution : We have given a triangle with hypotenuse = 12 units,

Opposite side = 7 , adjacent = x.

By the Pythagorean  theorem :

(hypotenuse )² = ( adjacent )² + ( opposite)².

Plug the values

(12)² = ( x )² + ( 7)².

144 =  ( x )² +  49.

On subtracting both sides by 49.

144 -49 =  ( x )²

95 =  ( x )²

Taking square root

√95 = x.

x = 9.7

Therefore, A) x = 9.7