Question

Find a cubic function with the given zeros.

7, -3, 2

Answer 1

$\bf x= \begin{cases} 7\\-3\\2 \end{cases}\implies \begin{cases} x=7\implies &(x-7)=0\\ x=-3\implies &(x+3)=0\\ x=2\implies &(x-2)=0 \end{cases}\\\\ -------------------------------\\\\ (x-7)(x+3)(x-2)=\textit{original polynomial} \\\\\\ (x^2-4x-21)(x-2)\implies x^3-4x^2-21x-2x^2+8x+42 \\\\\\ x^3-6x^2-13x+42$