Question

Q and r are independent events. if p(q) = 0.8 and p(r) = 0.2, find p(q and r).

Answer 1

P(R)=0.8
P(Q)=0.2
as they are independent
so
P(RandQ)=P(R)×P(Q)

Then

P(RandQ)=P(R)×P(Q)

               =0.8×0.2

               =0.16

Answer 2

Answer:

The solution is $P(q \cap r)=0.16$

Step-by-step explanation:

We need to calculate the $(p \ \text{and} \ q)$

Given:- $P(q)=0.8 \ \text{and} \ P(r) =0.2$  where q and r are independent events.

Since, Events are independent then $P(q \cap r)=q \times r$

⇒$P(q \cap r)=q \times r$

⇒$P(q \cap r)=0.8 \times 0.2$

⇒$P(q \cap r)=0.16$

Therefore, the solution is $P(q \cap r)=0.16$