Question

Question part points submissions used find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = t cos(t), y = t sin(t); t = π

Answer 1

r^2 = [tCos(t)]^2 + [tSin(t)]^2 = t^2(Sin(t)^2 + Cos(t)^2) = t^2
So the curve is a circle with the center at the origin.
When t=pi, x=-1 is the equation of the tangent to the curve at that point.