Respuesta :
50 + 5.5f < = 100
5.5f < = 100 - 50
5.5f < = 50
f < = 50/5.5
f < = 9.09....she can invite, at most, 9 friends
5.5f < = 100 - 50
5.5f < = 50
f < = 50/5.5
f < = 9.09....she can invite, at most, 9 friends
Answer:
Joann can afford maximum 9 friends in her party.
Step-by-step explanation:
Let she can invite x friends in her party.
Skateland charges fixed charges = $50 and $5.50 for each person.
So the total charges she has to pay for x friends = $(5.5x + 50)
Since Joann can spend at most $100.
So the inequality which will represent the expenditure will be
(5.5x + 50) ≤ 100
5.5x ≤ 100 - 50
5.5x ≤ 50
x ≤ [tex]\frac{50}{5.5}[/tex]
x ≤ 9.09
Therefore, Joann can afford maximum 9 friends in her party.