To determine the time when the ball would be higher than 12 feet off the ground, we use the equation given which relates time and the height. It is given as:
h(t)=-4t^2 + 16
By substituting 12 to the height, we solve for the value of t.
h(t)=-4t^2 + 16
12 =-4t^2 + 16
-4 = -4t^2
t = 0 s
Therefore, the ball would never reach a height of 12 feet or higher than that or it can represent that the ball is thrown at a height of 12 feet so any time greater than 0 the ball is higher than 12 feet.
