Question

A quarterback throws a football from a position that is 10 yards from the goal line and 15 yards from the sideline. his receiver catches it at a position that is 50 yards from the same goal line and 5 yards from the same sideline. find the distance of the throw

Answer 1

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Answer 2

The required distance of the throw is 41.2 yards.

To start solving this, we would be applying the formula of distance between two points

$\sqrt[2]{(x2 - x1)^{2} + (y2 -y1)^{2} }$

From the question, we are given the co-ordinates  of y = 10, 15, which is where the ball was thrown and x = 50, 5, which was where the ball landed. Now, using the above stated formula, we can find the required distance.

D = $\sqrt[2]{(50 - 10)^{2} + (5 -15)^{2} }$

D = $\sqrt[2]{(40)^{2} + (-10)^{2} }$

D = $\sqrt[2]{(1600) + (100) }$

D = $\sqrt{1700}$

D = ±41.2

Since distance can not be in negative, we conclude our answer to be 41.2 yards

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