Question

Answer? Multiple choice?

Answer 1

Given fraction is
$f(x) = \frac{x^2 + 4x + 3}{x^2 - 9}$

As we know fraction is not defined where denominator is equal to zero.

So let's find where denominator is zero.

$x^2 - 9 = 0$

We can factorize it as $a^2 - b^2 = (a+b)(a - b)$

So we can write given equation as

$(x+3)(x-3) = 0$

So x = 3 or x = -3.

So function is undefined at x = 3 and x = -3.

So option 3 is correct.