Question

A regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. It has a lateral surface area of 57 square centimeters. What is the surface area of the regular triangular pyramid?

Answer 1

57 cm^2 is equal to the lateral surface area, or the three sides in this case.

57/3= 19 cm^2 per side. Because the base is equal to the area of the side, this is the base area.

19+57= 76 cm^2 for sides+ base (total surface area)

Final answer: 76 cm^2

Answer 2

The surface area of the regular triangular pyramid is 76 square centimetres.

What is a regular triangular pyramid?

A triangular pyramid is a three-dimensional shape that has a triangular base and three triangular faces.

The lateral surface area is the area of all the sides of a 3-dimensional object excluding its base and top.

The surface area of a triangular pyramid is the sum of the areas of the four faces of the pyramid.  

What is the surface area?

The area of one face = lateral surface area / 3

57 / 3 = 19

The surface area = 19 x 4 = 76

To learn more about a pyramid, please check: https://brainly.com/question/9222686