Question

What is f(5) if f(1) = 3.2 and f(x + 1) = (f(x))?

Answer 1

$f(x + 1) = (5/2)*f(x) f(x + 1) = 2.5*f(x), f(1) = 3.2 f(2) = 2.5f(1) = 2.5*3.2 = 8 f(3) = 2.5f(2) = 2.5*8 = 20 f(4) = 2.5f(3) = 2.5*20 = 50 f(5) = 2.5f(4) = 2.5*50 = 125$

Answer 2

Answer:

$f(5)=125$

Step-by-step explanation:

The complete question is

What is f(5) if f(1) = 3.2 and f(x + 1) =5/2 (f(x))?

By given,

$f(1)=3.2$ and $f(x+1)=\frac{5}{2}(f(x))$

Now, we need to replace one be one until we get $f(5)$, because the given function is a sequence, so

For $x=1$

$f(x+1)=\frac{5}{2}(f(x))$

$f(1+1)=\frac{5}{2}(f(1))\\f(2)=2.5(3.2)=8$

Then, for $x=2$

$f(2+1)=\frac{5}{2}(f(2))\\f(3)=2.5(8)=20$

We repeat the process until we get $f(5)$,

For $x=3$

$f(3+1)=\frac{5}{2}(f(3))\\f(4)=2.5(20)=50$

For $x=4$

$f(4+1)=\frac{5}{2}(f(4))\\f(5)=2.5(50)=125$

Therefore, if $f(1)=3.2$  and $f(x+1)=\frac{5}{2}(f(x))$, then $f(5)=2.5(50)=125$