Question

what is 1 1/3 subtracted from its reciprocal?

Answer 1

Answer:

$\frac{-7}{12}$

Step-by-step explanation:

The given fraction is $1\frac{1}{3}$ or  $\frac{4}{3}$

reciprocal of the given fraction  $\frac{4}{3}$ will be  $\frac{3}{4}$

Now we have to calculate the difference of  $\frac{4}{3}$ and  $\frac{3}{4}$

- $\frac{4}{3}$  +  $\frac{3}{4}$ =  $\frac{-16+9}{12}$ =   $\frac{-7}{12}$

Therefore, answer is $\frac{-7}{12}$

Answer 2

The value of $1\frac{1}{3}$  subtracted from its reciprocal $\frac{3}{4}$ is  $- \frac{7}{12}$ (-7/12)

First, we will determine the reciprocal of the given number (fraction)

The given fraction is $1\frac{1}{3}$  (1 1/3)

NOTE: $1\frac{1}{3} = \frac{4}{3}$

The reciprocal of a given fraction is the fraction flipped upside down, that is the numerator becomes the denominator and the denominator becomes the numerator.

∴ The reciprocal of $\frac{4}{3} \ is \ \frac{3}{4}$     ( that is, the reciprocal of 1  1/3 is 3/4)

Now, To determine the value of  1 1/3 subtracted from its reciprocal, that is

$\frac{3}{4}-\frac{4}{3}$

The value is  

$\frac{3}{4}-\frac{4}{3} = \frac{3(3) - 4(4)}{12}$

$=\frac{9-16}{12}$

$=- \frac{7}{12}$

Hence, the value of $1\frac{1}{3}$  subtracted from its reciprocal $\frac{3}{4}$ is  $- \frac{7}{12}$

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