Respuesta :
First, convert 2.0 mL of AlCl3 to grams using the density, which is 2.48g/mL. So 2.48g/mL * 2.0 mL = 4.96g. Then find the molar mass of aluminum chloride and divide 4.96 by this number, which is 133.34g. 4.96g*(1mol/133.34g) = .0372 mols AlCl3. Check for significant digits though.
Answer:
0.00020 moles
Explanation:
Without overwhelming anybody who desires the correct answer, here it is.
The answer to both of the questions stating that you are to measure a specific solution and place it in a test tube is 0.00020 moles.
Hope this helps.