Let a₁ = the first number.
Because each number is 4 more than the number before it, the list of numbers forms an arithmetic sequence with a common difference of d = 4.
The n-th term is
[tex]a_{n} = a_{1}+(n-1)d[/tex]
The 200-th term is
a₂₀₀ = a₁ + (200 - 1)*4
= a₁ + 796
a₂₀₀ - a₁ = 796
Because a₂₀₀ is the last number on the list, the difference between the first and the last number on the list is 796.
Answer: The difference is 796.