An 8 Ω resistor is connected to a 6 V battery and another resistor in series. If the current in the circuit is 0.5 A, what is the resistance of the other resistor?
Let the resistance of another resistor be xΩ Current=0.5 A Voltage=6 V Total resistance= (8+x)Ω Current=voltage/resistance 0.5=6/(8+x) 4+0.5x=6 0.5x=2 ×=4Ω Answer is option D
