A 9 V battery is connected in series to four resistors as follows: R1 = 2 Ω, R2 = 4 Ω, R3 = 4 Ω, and R4 = 8 Ω. What is the total resistance of the circuit?
Since the four resistance are connected in series, the total resistance is sum of individual resistances. Total resistance= R1+R2+R3+R4 = (2+4+4+8)Ω = 18Ω 18 A is not the answer because A stamds for Ampere whivh is SI unit of electric current. Answer is option d