A 9 V battery is connected in series to four resistors as follows: R1 = 2 Ω, R2 = 4 Ω, R3 = 4 Ω, and R4 = 8 Ω. What is the total resistance of the circuit?

A. 0.5 Ω
B. 9 V
C. 18 A
D. 18 Ω

Respuesta :

Since the four resistance are connected in series, the total resistance is sum of individual resistances.
Total resistance= R1+R2+R3+R4 = (2+4+4+8)Ω = 18Ω
18 A is not the answer because A stamds for Ampere whivh is SI unit of electric current.
Answer is option d
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