Two lightbulbs each with a resistance of 20 Ω are connected in series to a voltage of 120 V. If a third lightbulb of 20 Ω is added to the circuit, how will the current change?

A. It will remain the same.
B. It will increase from 40 A to 60 A.
C. It will decrease from 30 A to 20 A.
D. It will decrease from 60 A to 20 A.

Respuesta :

Total resistance= 20 + 20=40Ω
Voltage=120v
Current= voltage/resistance= 30A

After adding another bulb:
Total resistance= 20+ 20 +20= 60Ω
Voltage=120v
Current=120/60= 20A

Answer is option C
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