Respuesta :
assuming each guest isn't a fatty and every guest eats only 1 portion
320 times 8oz=2560 oz needed
number of cans needed times oz per can=oz we need
n times 40=2560
divide both sides by 40
n=64
64 cans needed
320 times 8oz=2560 oz needed
number of cans needed times oz per can=oz we need
n times 40=2560
divide both sides by 40
n=64
64 cans needed
Answer:
Hence, 64 cans of beets are required.
Step-by-step explanation:
We are given:
Guests = 320
portions of beets served = 8 oz.
Total number of beets served=320×8= 2560 oz.
size of beet can = 40 oz.
Let 'n' be the total number of cans of beet required.
⇒ total number of beets served=n× size of beet can.
⇒ 2560=n×40
⇒ n=2560/40=64
Hence, the number of cans of beets required=64 cans.
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