[tex]C + O_2 ----\ \textgreater \ CO_2[/tex]
Here we have to find the limiting reagent.
Let's start with 0.2 moles of C.
So, moles of O2 require = 0.2 moles
but, there are 0.4 moles of O2 available.
So, O2 is excess agent.
Means C is limiting agent. Means calculation will be done with C.
So, moles of CO2 form = 0.2
so, mass of CO2 = 0.2 x 44 = 8.8g