There are 2 cones in the picture that are joined together at their base.
The radius (r) of the cone = 10 ft
The height (h) of the cone = 24 ft
Thus, the slant height (l) of the cone = [tex] \sqrt{ h^{2} + r^{2} } [/tex] = [tex] \sqrt{ 24^{2} + 10^{2}} = \sqrt{576 + 100} = \sqrt{676} [/tex] = 26 ft
Now, we have all the values, we can calculate the area.
The surface area of a cone including the base = [tex] \pi r^{2} + \pi rl[/tex]
But since we only need the area without the base so the surface area = [tex] \pi rl[/tex] = [tex] \pi *10 *26[/tex] = [tex]260 \pi [/tex]
That is the area of one cone without the base area.
The area of both the cones = [tex]2*260 \pi = 520 \pi [/tex]
