Answer:
Rational number Irrational number
3√25 √141
√256
[tex]1.\overline{1625}[/tex]
[tex]\dfrac{-11}{151}[/tex]
Step-by-step explanation:
Since we know that
Rational number are those numbers which can be written in the form of [tex]\frac{p}{q}[/tex] and it is non terminating but recurring number.
Irrational numbers are those numbers which can not be written in the form of [tex]\frac{p}{q}[/tex] and it is non terminating and non recurring number.
3√25 = 3×5 = 15 is rational number.
[tex]\dfrac{-11}{151}[/tex] is rational number because it is written in the form of [tex]\frac{p}{q}[/tex]
[tex]1.\overline{1.625}[/tex] is rational number because it is non terminating but repeating number.
√256 = 16 is rational number
√141 is irrational number.
Hence, Rational number Irrational number
3√25 √141
√256
[tex]1.\overline{1625}[/tex]
[tex]\dfrac{-11}{151}[/tex]