Respuesta :
the pieces are x,y,z length
the sum is 36
x+y+z=36
x is first, y is 2nd, z is 3rd
x=y/2
z=1+2y
subsitute
x+y+z=36
(y/2)+y+1+2y=36
(y/2)+3y+1=36
minus 1 both sides
(y/2)+3y=35
times both sides by 2
y+6y=70
7y=70
divide both sides by 7
y=10
the 2nd piece of ribbon is 10ft
the sum is 36
x+y+z=36
x is first, y is 2nd, z is 3rd
x=y/2
z=1+2y
subsitute
x+y+z=36
(y/2)+y+1+2y=36
(y/2)+3y+1=36
minus 1 both sides
(y/2)+3y=35
times both sides by 2
y+6y=70
7y=70
divide both sides by 7
y=10
the 2nd piece of ribbon is 10ft
Answer:
The length of the longest piece of the ribbon is:
21 feet
Step-by-step explanation:
It is given that:
A 36 – foot-long rope is cut into three pieces.
Let the length of first piece of ribbon= x
The length of second piece of ribbon= 2x
( since, the first piece of ribbon is half as long as the second piece of ribbon)
Also,
The third piece is 1 foot longer than twice the length of the second piece of ribbon.
i.e. the length of third piece is: 2(2x)+1
i.e.
The length of third piece= 4x+1
Hence, we have:
sum of the length of three pieces= 36
i.e.
x+2x+4x+1=36
i.e.
7x+1=36
i.e.
7x=36-1
i.e.
7x=35
On dividing both side of the equation by 7 we have:
x= 5
Hence, the length of first piece= 5 feet
Length of second piece= 2(5)=10 feet
and Length of Third piece = 2(10)+1= 21 feet