Respuesta :
check the picture below.
[tex]\bf \left. \qquad \right.\textit{internal division of a line segment} \\\\\\ I(5,9)\qquad J(9,10)\qquad \qquad 2:3 \\\\\\ \cfrac{I\underline{K}}{\underline{K} J} = \cfrac{2}{3}\implies \cfrac{I}{J} = \cfrac{2}{3}\implies 3I=2J\implies 3(5,9)=2(9,10) \\\\ -------------------------------\\\\[/tex]
[tex]\bf { K=\left(\cfrac{\textit{sum of "x" values}}{ratio1+ratio2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{ratio1+ratio2}\right)}\\\\ -------------------------------\\\\ K=\left(\cfrac{(3\cdot 5)+(2\cdot 9)}{2+3}\quad ,\quad \cfrac{(3\cdot 9)+(2\cdot 10)}{2+3}\right)[/tex]
so. the x-coordinate of K will then be at [tex]\bf \cfrac{(3\cdot 5)+(2\cdot 9)}{2+3}[/tex]
----------------------------------------------------------------------------------------------
[tex]\bf \cfrac{(3\cdot 5)+(2\cdot 9)}{2+3}\implies \cfrac{33}{5}\implies 6\frac{3}{5} \\\\\\ I(5,9)\impliedby \textit{to go from 5, to }6\frac{3}{5}\textit{ is just }1\frac{3}{5}\implies \cfrac{8}{5}\implies \cfrac{4\cdot 2}{5} \\\\\\ or\implies 4\cdot \cfrac{2}{5}\impliedby \textit{distance from 5 to }6\frac{3}{5}[/tex]
[tex]\bf \left. \qquad \right.\textit{internal division of a line segment} \\\\\\ I(5,9)\qquad J(9,10)\qquad \qquad 2:3 \\\\\\ \cfrac{I\underline{K}}{\underline{K} J} = \cfrac{2}{3}\implies \cfrac{I}{J} = \cfrac{2}{3}\implies 3I=2J\implies 3(5,9)=2(9,10) \\\\ -------------------------------\\\\[/tex]
[tex]\bf { K=\left(\cfrac{\textit{sum of "x" values}}{ratio1+ratio2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{ratio1+ratio2}\right)}\\\\ -------------------------------\\\\ K=\left(\cfrac{(3\cdot 5)+(2\cdot 9)}{2+3}\quad ,\quad \cfrac{(3\cdot 9)+(2\cdot 10)}{2+3}\right)[/tex]
so. the x-coordinate of K will then be at [tex]\bf \cfrac{(3\cdot 5)+(2\cdot 9)}{2+3}[/tex]
----------------------------------------------------------------------------------------------
[tex]\bf \cfrac{(3\cdot 5)+(2\cdot 9)}{2+3}\implies \cfrac{33}{5}\implies 6\frac{3}{5} \\\\\\ I(5,9)\impliedby \textit{to go from 5, to }6\frac{3}{5}\textit{ is just }1\frac{3}{5}\implies \cfrac{8}{5}\implies \cfrac{4\cdot 2}{5} \\\\\\ or\implies 4\cdot \cfrac{2}{5}\impliedby \textit{distance from 5 to }6\frac{3}{5}[/tex]
![Ver imagen jdoe0001](https://us-static.z-dn.net/files/d70/5087e006a894b0883a4a13d66f55c720.jpeg)
Answer:
The correct option is 2.
Step-by-step explanation:
It is given that the endpoints of the line segment are I(5, 2) and J(9, 10).
According to the section formula, if a point divide the line segment in m:n, then the coordinates of that point are
[tex](\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})[/tex]
The x-coordinate is also written as
[tex]x-coordinate=\frac{m}{m+n}(x_2-x_1)+x_1[/tex]
The distance between the x-coordinates is 4 units and [tex]x_1=5[/tex]. So, the fractions that will let him find the x-coordinate for point K is
[tex]\frac{m}{m+n}=\frac{2}{2+3}=\frac{2}{5}[/tex]
The required fraction is 2/5.
The x-coordinate of K is
[tex]x-coordinate=\frac{2}{5}(4)+5=\frac{33}{5}[/tex]
Therefore the correct option is 2.