Question

What is the equation of the line that passes through (4,3) and (2,2)

Answer 1

The Equation of (4,3) and (2,2) is y=1/2x+1

Answer 2

Answer:

The equation of line is $y=\frac{1}{2}(x)+1$.

Step-by-step explanation:

Given information: The line passes through the point (4,3) and (2,2).

If a line passes through the points $(x_1,y_1)$ and $(x_2,y_2)$, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through the point (4,3) and (2,2), so the equation of line is

$y-3=\frac{2-3}{2-4}(x-4)$

$y-3=\frac{-1}{-2}(x-4)$

$y-3=\frac{1}{2}(x-4)$

Using distributive property, we get

$y-3=\frac{1}{2}(x)+\frac{1}{2}(-4)$

$y-3=\frac{1}{2}(x)-2$

Add 3 on both sides.

$y=\frac{1}{2}(x)-2+3$

$y=\frac{1}{2}(x)+1$

Therefore the equation of line is $y=\frac{1}{2}(x)+1$.