A. The fact that the question tells us that that two triangles are similar to each other, tells us that the corresponding sides of the triangles are proportionate to each other. This means that side AD is proportionate to AC and DE is proportionate to BC. This also means that the proportion that we get from AD and AC has to be equal to DE and BC (AD/AC has to equal AD/AC). With this, we can set up the following:
x 10
-------- = ------------
x+4 x+7
then, if we cross multiply, we get
x(x+7) = 10(x+4)
then after we simplify, we get
x^2 + 7x = 10x +40
then we solve it for zero and we get
x^2 -3x -40 =0 (the reason we solve for zero is to that we can factor it)
Then we factor
(x-8) = 0 and (x + 5) = 0
and when we solve for x, we get
x =8 and x = -5, but since a negative number doesn't make sense, we find that x = 8 is the answer to part A.
But this can easily be checked with the proportion (AD/AC has to equal AD/AC)
x 10
-------- = ------------
x+4 x+7
so if we plug in 8 for x, we get
8 10
-------- = ---------- and when simplified, we get 2/3 for both.
12 15
B. To figure of the perimeter, we must use the Pythagorean Theorem.
a^2 + b^2 = c^2
we will use a = 8 (this is what we got for x), b = 10 (this is given), and c for the hypotenuse.
Therefore, we get
8^2 + 10^2 = c^2
64 + 100 = c^2
164 = c^2
__
c = 2 /41 (supposed to be 2 squareroot 41)
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Then you add 8, 10 and 2 root 41 to get your answer to be 18 + 2 /41 as the perimeter.
This is the best that I've got.