Respuesta :
In general number of choosing r things from the group of n number of things(When order doesn't matter) = [tex]^nC_r[/tex]
We can expand [tex]^nC_r[/tex] as [tex]^nC_r = \frac{n!}{r! * (n-r)!} [/tex]
So same way we can find number of way to listen 4 different cds from 15 cds = [tex]^{15}C_4[/tex]
Which we can calculate as
[tex]^{15}C_4 = \frac{15!}{4!* (!5 - 4)!} = \frac{15!}{4! * 11!} [/tex]
[tex]= \frac{15 * 14 * 13 * 12 * (11!)}{4*3*2*1 * (11!)} = \frac{15*14*13*12}{4*3*2*1} = 5* 7 * 13 * 3 *1 [/tex]
= 1365
We can expand [tex]^nC_r[/tex] as [tex]^nC_r = \frac{n!}{r! * (n-r)!} [/tex]
So same way we can find number of way to listen 4 different cds from 15 cds = [tex]^{15}C_4[/tex]
Which we can calculate as
[tex]^{15}C_4 = \frac{15!}{4!* (!5 - 4)!} = \frac{15!}{4! * 11!} [/tex]
[tex]= \frac{15 * 14 * 13 * 12 * (11!)}{4*3*2*1 * (11!)} = \frac{15*14*13*12}{4*3*2*1} = 5* 7 * 13 * 3 *1 [/tex]
= 1365
Answer:
32,760 is the correct answer, the first person is wrong! Took the test and this is it!
Step-by-step explanation: