Question

A 0.55 kg car is placed at the top of a ramp. The ramp is 2.5 m long and is
positioned at an angle of 40°.
It is released from rest and accelerates down the ramp.
What is the velocity of the car when it reaches the bottom of the ramp?
*Use 9.8 for the acceleration due to gravity
a
b
C
O d
5.61 m/s
3.17 m/s
2.53 m/s
4.99 m/s

Answer 1

The velocity of the car when it reaches the bottom of the ramp is 15.8 m/s.

To find the velocity of the car when it reaches the bottom of the ramp, we can use the principles of kinematics. The acceleration of the car down the ramp can be determined using the equation: acceleration = gravity * sin(angle). Plugging in the given values, we get: acceleration = 9.8 * sin(40°) = 6.32 m/s².

Next, we can use the equation: final velocity = initial velocity + acceleration * time. Since the car starts from rest, the initial velocity is 0. Plugging in the values, we get: final velocity = 0 + 6.32 m/s² * 2.5 m = 15.8 m/s.

Therefore, the velocity of the car when it reaches the bottom of the ramp is 15.8 m/s.